Paint for a 8×10 room
A 8×10 ft room with 8 ft ceilings has 288 sq ft of wall. For the standard 2 coats you need 2 gallons of paint (≈ $70).
| Wall area | 288 sq ft |
|---|---|
| 1 coat | 1 gal |
| 2 coats (standard) | 2 gal |
| 3 coats (big color change) | 3 gal |
| 2 coats, textured/bare walls | 3 gal |
| 2 coats + ceiling | 3 gal |
| Estimated cost (2 coats) | ≈ $70 |
Adjust it
Change the size, ceiling height, coats, or surface below:
How much paint do I need?
| Paintable area | |
|---|---|
| Coverage needed (with coats) | |
| Estimated paint cost |
Estimate for walls (2 coats by default). Coverage assumes smooth, primed drywall; bare or textured walls absorb more — pick "Textured." Small doors/windows are left in as a cut-in buffer. Cost is an estimate (as of June 2026) — confirm the price of your chosen paint.
The math: wall area = 2 × (8 + 10) × 8 = 288 sq ft; × 2 coats = 576 sq ft; ÷ 350 sq ft per gallon (smooth drywall) = 1.65 → round up to 2 gallons. Read the full guide: How much paint do I need?
Other room sizes
Last updated: 2026-07-03.
Coverage from Sherwin-Williams
(350–400 sq ft/gal smooth drywall) and Behr guidance. Cost is a US-average estimate.